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Chlorine is prepared in the laboratory by treating manganese dioxide (MnO_(2)) with aqueous hydrochloric acid according to the reaction. 4HCl(aq)+MnO_(2)(s) rarr 2H_(2)O(l)+MnCl_(2)(aq)+Cl_(2)(g) How many grams of HCl react with 5.0 g of manganese dioxide ? (Atomic mass of Mn = 55 u) |
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Answer» Solution :1 mole of `MnO_(2)`, i.e, `55+32=87g MnO_(2)` REACT with 4 MOLES of HCl, i.e., `4xx36.5g=146g` of HCl. `therefore "5.0 G of MnO"_(2)" will react with HCl"=(146)/(87)xx5.0 g=8.40g` |
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