Chemistry...Doubt....Please Help me out.

1.	Chemistry...Doubt....Please Help me out.
Answer» HELLO USER, Here's your answer: REACTION: H₂ + Cl₂ ----> 2HCl Volume ratio = 1 : 1 : 2 (1 volume of H₂, 1 volume of Cl₂ and 2 VOLUMES of HCl) Given that, 4cm³ of Hydrogen is unreacted. *So, volume of reacted mixture = (36 - 4) cm³ = 32 cm³ Now, 1 volume of H₂ = $\frac{1}{2} \times 32 = 16cm^{3}$ Again, 1 volume of Cl₂ = $\frac{1}{2} \times 32 = 16cm^{3}$ ACTUAL volume of Hydrogen given at first = (16 + 4) cm³ = 20 cm³ Hence, original COMPOSITION of the mixture was, 20cm³ of Hydrogen and 16 cm³ of Chlorine.* Hope my answer is satisfactory... THANKS!

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