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Chemistry class 12th solid state help plz |
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Answer» Answer: Number of atoms in close packaging = 0.5 mol 1 has 6.022 ×1023 PARTICLES So that Number of close−packed particles = 0.5 × 6.022 × 1023 = 3.011 × 1023 Number of tetrahedral VOIDS = 2 × number of atoms in close packaging Plug the values we get Number of tetrahedral voids = 2 × 3.011 × 1023 = 6.022 × 1023 Number of octahedral voids = number of atoms in close packaging So that Number of octahedral voids = 3.011 × 1023 Total number of voids = Tetrahedral void + octahedral void = 6.022 × 1023 + 3.011 × 1023 = 9.03 × 1023 Explanation: |
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