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Chemical equilibrium is attained in a reversible reaction carried in a close container and is of dynamic nature. The value of equilibrium constant may be expressed either as `K_(p)" and " K_(c)` and the two are related to each other as : `K_(p) =K_(c)(RT)^(Deltang)` Free energy change `(DeltaG)` at equilibrium point is zero. The value of equilibrium constant gives the extent to which a particular reation has proceeded to attain the equilibrium . Its value gets reversed if the reaction is reversed and becomes the square root of the initial value if the reaction is divided by 2. For the reaction `PCI_(3)(g)+ CI_(2) (s) hArr PCI_(5) (g)` The value of `k_(c) " at " 250^(@)C " is " " mol"^(-1) L^(-1)`. The value of `k_(p)` at the same temperature will be :A. `0.61 atm^(-1)`B. `0.56 atm^(-1)`C. `0.83 atm^(-1)`D. `0.46 atm^(-1)` |
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Answer» Correct Answer - A `K_(p) =K_(c)(RT)^(Deltang) =(26 "mol" L^(-1))` `x (0.0821 L atm K^(-1) mol^(-1) xx 523 K^(-1))` `= 0.61 K` |
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