1.

Check whether the no. 21^n can end with digit 0 or not for any natural no.I

Answer» GIVEN,

=  21^n

= ( 3 * 7 ) ^ n

= 3^n * 7^n

For any number to END with 0 it should be in the FORM of 2^m * 5^n, but here it is not so.Hence,21^n can't end with 0.


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