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Check whether the following are quadratic equations (2x-1)(x-3)=(x+5)(x-1) |
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Answer» yes, by multiplying the terms we get: (2x-1)(x-3)=(x+5)(x-1) 2x2-x-6x+3=X2+5x-x-5 2x2-7x+3=X2+4x-5 now mowing RHS side equation to LHS side: we will get, 2x2-x2-7x-4x+3+5=0 = x2-11x+8=0 hence the equation has degree as 2 so it is a quadratic equation (2x-1)(x-3) = (x+5)(x-1) => By multiplying the terms => 2x(x-3)-1(x-3) = x(x-1)+5(x-1) => 2x²-6x-x+3 = x²-x+5x-5 => 2x²-7x+3 = x²+4x-5 => 2x²-x²-7x-4x+3+5 = 0 => x²-11x+8 = 0 So, this equation satisfies that it is a Quadratic Equation. ax² + bx + c = 0 |
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