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Check whether 3 and -2 are the zeros of the polynomial p(x)=x2-×-6 |
Answer» p(x) = x2 × (-6)=> put 3 in place of x 3 = (3×2) × (-6) 3= 6× -6 3= - 36 = -36/3 = -12. p(x) = x2 × (-6)=> put -2 in place of x -2= (-2 × 2) × (-6) -2= -4 × -6 -2 = 24 = 24/-2 = -12 |
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