1.

Check whether 2019 a term of the A. S 5, 8, 11,....​

Answer»

Given \: sequence \: 5,8,11 \ldots

i) a_{2} - a_{1} = 8 - 5 = 3

ii) a_{3} - a_{2} = 11 - 8 = 3

\blue {a_{2} - a_{1} = a_{3} - a_{2} = 3}

\<klux>THEREFORE</klux> Given \: sequence \: is \:an \:A.P

Now ,First \:term ( a ) = 5

Common \: difference (d) = 3

Let \: n^{th} \:term \: of \: A.P = 2019

\implies a + (n-1)d = 2019

\implies 5 + (n-1)\times 3 = 2019

\implies (n-1)\times 3 = 2019 - 5

\implies (n-1)\times 3 = 2014

\implies n-1= \frac{ 2014}{3}

\implies n= \frac{ 2014}{3} + 1

\implies n= \frac{ 2014 + 3}{3}

\implies n= \frac{ 2017}{3}

But \: \red{( Number \:terms \:of \: an \:A.P }

\red{ should \:not \:be \: a \: fraction) }

Therefore.,

\green { 2019 \: is \:not \: a \: term \:of }

\green { given \:A.P .}

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