Check: 1" term of LHS =43x-7 -1- 31-21 - 3131x4--52-13- 31x4 31-13 79

1.	Check: 1" term of LHS =43x-7 -1- 31-21 - 3131x4--52-13- 31x4 31-13 79 -39 + 7940Hence, LHS 31 93 93 93Again, RHS = -7%Therefore, LHS = RHS31 x 69Exercise 14.1Q1.(h) 7ySolve the following equations and verify the result.(a) 2(0.35y - 1) + 2.3y = 8 (b) 2x - 45 = 15 (c) 3a -(e) 3(5a - 2) + 5(2a + 4) = 4 (6) 9x + 5 = 4(x - 2) + 8(g) 15ly - 4) - 2ly - 9) + 5(y + 6) = 0уRam and Mohan are brothers. Ram's present age is three yeMohan. If the sum of their present age is 27, find their ages.Sum of three consecutive multiples of 8 is 96. Find the multipQ2.Q3.Mathematics for Class 8 - CBSE
Answer» SORRY I COULD NOT ANSWER THIS QUESTION NEXT TIME I WILL SURELY ANSWERING YOU Answer: let Mohan's present age be x Then Ram's age = 2x+3 According to the question: x+2x+3=27 3x=27-3 3x=24 x=24/3 x=6 Therefore , Ram's age=x=6 years Mohan's age= 2x+3 = 2(6)+3 = 15 years

Check: 1" term of LHS =43x-7 -1- 31-21 - 3131x4--52-13- 31x4 31-13 79 -39 + 7940Hence, LHS 31 93 93 93Again, RHS = -7%Therefore, LHS = RHS31 x 69Exercise 14.1Q1.(h) 7ySolve the following equations and verify the result.(a) 2(0.35y - 1) + 2.3y = 8 (b) 2x - 45 = 15 (c) 3a -(e) 3(5a - 2) + 5(2a + 4) = 4 (6) 9x + 5 = 4(x - 2) + 8(g) 15ly - 4) - 2ly - 9) + 5(y + 6) = 0уRam and Mohan are brothers. Ram's present age is three yeMohan. If the sum of their present age is 27, find their ages.Sum of three consecutive multiples of 8 is 96. Find the multipQ2.Q3.Mathematics for Class 8 - CBSE

Answer»

SORRY I COULD NOT ANSWER THIS QUESTION NEXT TIME I WILL SURELY ANSWERING YOU

Answer: let Mohan's present age be x

Then Ram's age = 2x+3

According to the question:

x+2x+3=27

3x=27-3

3x=24

x=24/3

x=6

Therefore ,

Ram's age=x=6 years

Mohan's age= 2x+3 = 2(6)+3 = 15 years