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छा - ४396. | ;500 - jwe| अ el ¥ 4800 - ; बाDigJie 2B S bibK IR U 41 - 00 किसके : :। ४.

Answer»

Let theta = x

LHS:sinx-cosx+1/ sinx+cosx -1 =(sinx-cosx+1)*(sinx+cosx+1) /(sinx+cosx -1)*(sinx +cosx+1) =(sinx +1)^2 - (cosx)^2 / (sinx +cosx)^2 - (1)^2 =sin^2 x+2sinx+1-cos^2 x/ sin^2 x+cos^2 x+2sinxcosx-1 =2sin^2 x+2sinx/ 2sinxcosx =2sinx(sinx +1)/ 2sinxcosx =sinx+1/cosx =(1+sinx)*(1-sinx)/ (cosx) *(1-sinx) = cosx/(1-sinx) (dividing num. and den. by cosx) =1/secx-tanx= RHS

Hence proved



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