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`CH_(3)NH_(2)` (0.12 mole, `pK_(b)`=3.3) is added to 0.08 moles of HCl and the solution is diluted to on litre, resulting pH of solution is :A. 10.7B. 3.6C. 10.4D. 11.3 |
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Answer» Correct Answer - C `CH_3NH_2 + HCl to CH_3NH_3Cl` `{:("Mole",0.12,0.08,0),("Mole",0.04,-,0.08):}` pOH=pKb + log = 3.6 pH=10.4 |
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