1.

CH_(3)CHOO_((1))+C_(2)H_(5)OH_((1))hArrCH_(3)COOC_(2)H_(5(1))+H_(2)O_((1)) In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. H_(2)SO_(4). On equlibrium being attained

Answer»

MOLE of ETHYL acetate is formed
2 mole of ethyl acetate are formed
`1//2` moles of ethyl acetate is formed
`2//3` moles of ethyl acetate is formed

Solution :In presence of little `H_(2)SO_(4)` (as catalyst) about 2/3 mole of each of `CH_(3)COOH and C_(2)H_(5)OH` react to from 2/3 mole of the product at equilibrium.


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