1.

CH_(3)CH_(2)CH=CH_(2)+HBr overset(ROOR)to underset("major")((X))+underset("Minor")((Y)) (X) and (Y) respectively are

Answer»

`BrCH_(2)CH_(2)-CH=CH_(2) and C_(2)H_(5)-CHBr-CH_(3)`
`C_(2)H_(5)-CH_(2)CH_(2)-Br and Br-CH_(2)CH_(2)CH=CH_(2)`
`C_(2)H_(5)-CH_(2)CH_(2)-Br and C_(2)H_(5)-CHBr-CH_(3)`
`C_(2)H_(5)-CHBr-CH_(3) and C_(2)H_(5)-CH_(2)CH_(2)Br`

Solution :In PRESENCE of peroxides, addition of HBr FOLLOWS anti-Markovnikov's rule.
`CH_(3)CH_(2)CH=CH_(2)+HBr underset(("Anti-Mark. Addn."))overset(ROOR)to underset((X))(CH_(3)CH_(2)CH_(2)CH_(2)Br)+underset((Y))(CH_(3)CH_(2)-CHBr-CH_(3))`


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