1.

CH_3 CH_2 CH_2 CH_3 overset(Cl_2)underset(hv)(to) underset("(monochlorination products)") (A + B) The approximate ratio of percentage yields of A and B formed in the above reaction is

Answer»

`50 : 50`
`72 : 28`
`45 : 55`
`60 : 40`

Solution :n-Butane has two types of H-atoms (six `1^(@)` and FOUR `2^(@)`) , therefore , it gives two monochloro-derivates , i.e., 2-chlorobutane (A) and 1-chloro-butane (B) . Their relative percentage YIELDS are
`("AMOUNT of A")/("Amount of B") = (4)/(6) xx (3.8)/(1.0) = (15.2)/(6.0) = (72% )/(28%)`


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