1.

CH_(3)CH_(2)Brunderset(alc.)overset(NaCN)toCH_(3)CN true, hence (CH_(3))_(3)CBrunderset(alc.)overset(NaCN)toA. Hence A is,

Answer»

`(CH_(3))_(3)C-CN`
`(CH_(3))_(3)C-CN`
`CH_(3)-CH=CH-CH_(3)`
`CH_(3)-CH_(2)-CH=CH_(2)`

Solution :CN is stronger nucliophile causesloss of HBr instead of NUCLEOPHILIC SUBSTITUTION REACTION.


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