1.

CH_(3)-CH_(2)-Br on treatment with LiAlH_(4) gives ethane gas while (CH_(3))C-Br on the same treatment gives H_(2) as because

Answer»

The FORMER is `S_(N^(2))` and LATER is E2 reaction
The former is E2 an later is `S_(N^(2))` reaction
The former is `S_(N^(1))` and later is E2 reaction
The former is E2 and later is `S_(N^(1))` reaction

Solution :


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