1.

CH_(3)Br+Nu^(-)rarrCH_(3)Nu+Br^(-) The decreasing order of the rate of the above reaction with nucleophiles (Nu^(-)) I to IV is : [Nu^(-)=(I)PhO^(-),(II)AcO^(-),(III)HO^(-),(IV)CH_(3)O^(-)]

Answer»

`IVgtIIIgtIIgtI`
`IgtIIgtIIIgtIV`
`IIgtIVgtIIIgtI`
`IVgtIIIgtIgtII`

Solution :The reaction follows `S_(N)2` mechanism so STRONGER the BASE, the better its nucleophilicity as :
`CH_(3)O^(-)gtOH^(-)gtPhO^(-)gtAcO^(-)`


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