`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")to`Z Where Z isA. `CH_(3)-Cunderset(Br)underset(|)(H)-(CH_(2))_(5)COOH`B. `BrCH_(2)-(CH_(2))_(6)COOH`C. `CH_(2)=CH-(CH_(2))_(5)-CH_(2)OH`D. `C_(6)H_(5)COOH`

`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")to`Z Where

1.	`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")to`Z Where Z isA. `CH_(3)-Cunderset(Br)underset(\|)(H)-(CH_(2))_(5)COOH`B. `BrCH_(2)-(CH_(2))_(6)COOH`C. `CH_(2)=CH-(CH_(2))_(5)-CH_(2)OH`D. `C_(6)H_(5)COOH`
Answer» Correct Answer - B `CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("peroxide")to underset(Br)underset(\|)(CH_(2))-(CH_(2))_(6)-COOH`

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`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")to`Z Where Z isA. `CH_(3)-Cunderset(Br)underset(|)(H)-(CH_(2))_(5)COOH`B. `BrCH_(2)-(CH_(2))_(6)COOH`C. `CH_(2)=CH-(CH_(2))_(5)-CH_(2)OH`D. `C_(6)H_(5)COOH`

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