1.

CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")toZ Where Z is

Answer»

`CH_(3)-Cunderset(Br)underset(|)(H)-(CH_(2))_(5)COOH`
`BrCH_(2)-(CH_(2))_(6)COOH`
`CH_(2)=CH-(CH_(2))_(5)-CH_(2)OH`
`C_(6)H_(5)COOH`

Solution :`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)OVERSET("PEROXIDE")to underset(Br)underset(|)(CH_(2))-(CH_(2))_(6)-COOH`


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