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Cesium chloride is formed according to the following equation Cs (s) + 0.5 Cl_(2) (g) to CsCl (s) The enthalpy of sublimation of Cs, enthalpy of dissociation of chlorine, ionization energy of Cs & electron gain enthalpy of chlorine are 81.2,243.0, 375.7 and –348.3 kJ mol^(-1). The energy change involved in the formation of CsCl is –388.6 kJ mol^(-1) . Calculate the lattice energy of CsCl. |
| Answer» SOLUTION :`-618.7 KJ MOL^(-1)` | |