1.

Certain force acting on a 20 kg mass changes its velocity from 5 m/s to 2 m/s.. calculate the work done by the force​

Answer»

Answer:

The work done by the force is –210 JOULE.

____________________________

Explanation:

Given:

  • Mass (m) = 20 kg.
  • Initial VELOCITY (u) = 5 m/s.
  • Final velocity (v) = 2 m/s.

_________________________

To FIND:

We have to find the work done by the force.

_________________

Solution:

We know that,

Work done = Force × distance

⇒ W = F × s

[Since F = ma and s = (v²– u²/2a)]

⇒W = ma{v²– u²/2a}

= 20*a*{(2²– 5²/2a)}

= 20{(4-25/2)}

= 10 × –21 = –210 Joule.

___________________________________

Thus, –210 Joule is the required answer.


Discussion

No Comment Found

Related InterviewSolutions