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Centre (a cos alfa,a sin alfa) and radius afind the equation of circle |
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Answer» Step-by-step explanation: Given (a COS alpha ‚a sin alfa ) RADIUS = r^2a eqn of circle :( x - xo )^2 +( y -yo) ^2 = r^2 = ( x - a cos alfa )^2 + ( y - a sin alfa )^2 = a^2 x^2 + y^2 - 2 a cos alfa - a sin alfa + a^2(cos^2 alfa + sin^2 alfa ). = a^2 x^2 +y^2 - 2 a cos alfa - a sin alfa + a^2 =a^2. «a cos^2 alfa +a sin^2 alfa = 1 »
x^2 + y^2 - 2acosalfa - 2 asin alfa = 0 HENCE proved |
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