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| 1. |
Centre (0,2) and radius 2. Find the equation of the circle |
| Answer» Given h=0 k=2 and r=2Equation of the circle (x-h)^2+(y-k)^2=r^2(x-0)^2+(y-2)^2=(2)^2x^2+y^2+4-4y=4x^2+y^2-4y=0 | |