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center of the circle 2x^2+2y^2+ax+by+c=0 is (3,-4) then what is the value of a and b ? |
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Answer» x coordinate of center= -(0.5*coefficient of x)/coefficient of x² => 3=-a/4=> a=-12 y coordinate of center= -(0.5*coefficient of y)/coefficient of y² => -4=-b/4=> b=16 answer is wrong check it ! |
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