1.

"CCl"_(3)-NO_(2) can be obtained by

Answer»

`CH_(3)-NO_(2)` reaction with `PCl_(5)`
`CH_(3)-NO_(2)` reaction with `Cl_(2)` in presence ORF NAOH
`CHCl_(3)` reaction with `HNO_(3)`
`CH_(3)COOH` reacts with `HNO_(3)`

Solution :`CH_(3)-NO_(2)overset(Cl_(2)//NaOH)to" CCL"_(3)-NO_(2)`


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