Carbon monoxide reacts with oxygen to form carbon dioxide according to the equation 2CO+O_(2)=2CO_(2). In an experiment, 400mL of carbon monoxide and 180mL of oxygen were allowed to react , when 80% of carbon monoxide was transformed to carbon dioxide. All the volumes were measured under the same conditions of temperature and pressure. find out the composition of the final mixture.

Carbon monoxide reacts with oxygen to form carbon dioxide according to

1.	Carbon monoxide reacts with oxygen to form carbon dioxide according to the equation 2CO+O_(2)=2CO_(2). In an experiment, 400mL of carbon monoxide and 180mL of oxygen were allowed to react , when 80% of carbon monoxide was transformed to carbon dioxide. All the volumes were measured under the same conditions of temperature and pressure. find out the composition of the final mixture.
Answer» Solution :`2CO+O_(2)=2CO_(2)` 2 vol 1 VOLT 2 vol From the above equation, it is observed that volume of oxygen REQUIRED for the transformation of carbon monoxide into carbon dioxide is half the volume of carbon monoxide and the volume of carbon dioxide produced is same as that of carbon monoxide. volume of carbon monoxide transformed `=(80xx400)/(100)=320mL` HENCE, volume of oxygen required for transformation `=(1)/(2)xx320=160mL` Volume of carbon dioxide produced =320mL So, the composition of FINAL MIXTURE is Carbon monoxide `=(400-320)=80mL` Carbon dioxide =320mL Oxygen =180-160=20mL.