1.

Carbon dioxide is end product of metabolism as shown: C_(6)H_(12)O_(6)+O_(2)rarrCO_(2)+H_(2)O Calcualte daily production of CO_(2) (in grams) assuming each person consumes 5xx10^(2) gm glucose perday and worlds' population is 3.6 bilion.

Answer»

`6xx19^(10)`
`264xx10^(10)`
`10^(10)`
`44xx0^(10)`

Solution :`n_("glucose")=(3.6xx10^(9)xx5xx10^(2))/(180)=10^(10)`


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