1.

Car - 1000 kg standingTruck - 7000 kg moving with 10 m/sm, = 1000 kgu1 =0 m/s m₂ = 7000kgmtMylly - mivet M₂u1000X0 + 7000xlo - v licoot7000)70000 = v(8000)Foove = v V = 8.75​

Answer»

Explanation:

GIVEN : m=1000 kg u=10 m/s t=10 s

Applied FORCE F=1000 N (forwards)

Retarding force f=500 N (backwards)

Acceleration of the CAR in forward direction a=

m

F−f

=

1000

1000−500

=0.5 m/s

2

USING v=u+at

∴ v=10+0.5×10=15 m/s



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