Capacitance of a capacitor becomes 43 times its original value if a dielectric slab of thickness t=d2 is inserted between the plates (d = separation between the plates). Then the dielectric constant of the slab is

Capacitance of a capacitor becomes 43 times its original value if a di

1.	Capacitance of a capacitor becomes 43 times its original value if a dielectric slab of thickness t=d2 is inserted between the plates (d = separation between the plates). Then the dielectric constant of the slab is
Answer» Capacitance of a capacitor becomes $\frac{4}{3}$ times its original value if a dielectric slab of thickness $t = \frac{d}{2}$ is inserted between the plates (d = separation between the plates). Then the dielectric constant of the slab is

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Capacitance of a capacitor becomes 43 times its original value if a dielectric slab of thickness t=d2 is inserted between the plates (d = separation between the plates). Then the dielectric constant of the slab is

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