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Can u please help me with this question??1.the width of sudha’s garden is 2/3 of its length . if its perimeter is 40m, find its dimensions.think its a tricky one.hoping for quick response

Answer»

Answer:

LET LENGTH= X

width= 2/3× x

assuming the garden to be rectangular

perimeter= 2(l+w)

i.e 40= 2(x+2x/3)

40= 2(5x/3)

finally we get x= 12m

thus length is 12 and width is 8

and area = 12×8= 96m^2



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