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Can someone help me out with this problem - Find 2 numbers such that their mean proportion is 24 and third proportion is 1536

Answer»

Let the two NUMBERS be x and y.


GIVEN that Mean PROPORTION of two numbers is 24.


= > \sqrt{xy} = 24


= > x * y = 24


= > xy = 576


= > x = (576/y) ----- (1)


Given that Third proportion is 1536.


= > y^2 = x * 1536 ------ (2)



Substitute (1) in (2), we get


= > y^2 = (576/y) * 1536


= > y^3 = 576 * 1536


= > y^3 = 884736


= > y = 96.



Substitute y = 96 in (1), we get


= > x = (576/y)


= > x = (576/96)


= > x = 6.



Therefore, the two numbers are 6 and 96.



Hope this helps!


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