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Can anyone give me solution of my question fast i will mark brainlist answer |
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Answer» Answer: It is a proof. Step-by-step explanation: prove: 2 T₆ - 3 T₄ + 1 = 0 LHS = = 2 (Sin⁶ x + Cos⁶ x) - 3 (Sin⁴ x + Cos⁴ x) + 1 = 2 (Sin² x + Cos² x) (Sin⁴ x - Sin² x Cos² x + Cos⁴ x) - 3 (Sin⁴ x + Cos⁴ x) + 1 by USING the formula for a³ + b³ = (a+b)(a²-ab+b²) = - 2 Sin² x Cos² x - Sin⁴ x - Cos⁴ x + 1 = - (Sin² x + COs² x )² + 1 = -1 + 1 = 0 = RHS Proved. |
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