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Calulate molality of 2.5 g of ethanoic acid in 75g of benzene |
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Answer» MOLECULAR wt of ethanoic acid = 46 Molality = wt. of SOLUTE x 1000 / molecular wt.of solute x wt, of SOLVENT in GRAMS = 2.5 x 1000 / 46 x 75 = 0.72m |
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