Saved Bookmarks
| 1. |
Caleulate energy of one mole of photonsof radiation whose frequency Is 5 10piSe |
|
Answer» Energy of one photon is given by the expression E = hVwhere, h = PlancKs constant = 6.636 x 10^-34J s-1V= Frequency of radiation = 5x 10^14Hz= 5 x 10^14s-1.E= (6.636 x 10^34J s-1 x 5 x 10^14s-1)= 33.18 x 1020JOne mole of photon = 6.023 x 10^23photonsTherefore, Energy of one mole of photon = (6.023 x 10^23x 33.18 x 10^-20J) = 199.84 x 10^3JEnergy of one mole of photon = 199.84 kJ |
|