1.

Calculation the molarity and normality of a solution containing "9.8 g of "H_(2)SO_(4) in "250 cm"^(3) of the solution.

Answer»

Solution :Mass of `H_(2)SO_(4)` dissolved = 9.8 g,`"Volume of the solution = 250 cm"^(3)="0.250 L"`
Calculation of molarity : MOLAR mass of `H_(2)SO_(4)="98 g MOL"^(-1)`
`therefore"No. of moles of "H_(2)SO_(4)=("Mass in g")/("Molar mass")=("9.8 g")/("98 g mol"^(-1))="0.1 mole"`
Calculation of normality : Eq. mass of `H_(2)SO_(4)=("Mol. mass of "H_(2)SO_(4))/("Basicity of "H_(2)SO_(4))=(98)/(2)=49`
`therefore"No. of g equivalent of "H_(2)SO_(4)=("Mass in g")/("Eq. mass")=(9.8)/(2)=0.2`
`"Noramlity "=("No. of g eq of the SOLUTE")/("Volume of solution in LITRES")=("0.2 g eq")/("0.250 L")="0.8 g eq L"^(-1)="0.8 N".`


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