Calculatethe totalnumberof degressof freedompossessedby themoleculesin

1.	Calculatethe totalnumberof degressof freedompossessedby themoleculesin onecm^3 ofH_2gasat NTP .
Answer» SOLUTION :22400`cm^2`of EVERY gascontains`6.02 XX 10^(23)`molecules ` therefore ` Numberof moleculesin `1 cm ^3 ` of ` H_2 ` gas`=( 6.02xx 10^(23))/( 22400 ) = 0.26875xx 10^(20)` Numberof degreesof freedomof a` H_2` gasmolecule = 5 ` therefore `Totalnumberof DEGRESS of freedomof `0.26875xx 10^(20)`molecules `= 0.26875xx 10^(20) xx 5 = 1.34 375xx 10^(20)`

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