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Calculatethe pH at whichan acidindicator with K_(a)= 1xx 10^(5) changescolourwhenindicator concentrationis 1 xx 10^(-3)M . Alsorport the pH at whichcoloured ionsare 80 %present. |
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Answer» SOLUTION :Forindicatordissociation equilibrium `HlnhArr H^(+)+In^(-)` ColourAColour B ` K_(In) = ([H^(+)][In^(-)])/([HLN]) ` `rArr1 xx 10^(-5) = ([H^(+)]xx 80//100)/(20//100)` ` :.[ H^(+)] = 0.25 xx 10^(-5)` `:. PH = 5.6020` |
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