1.

Calculatethe number of m.e and equivalent of NaOH present in 1 litre of N/10 NaOH solution .

Answer»

Solution :Number of m.e = normaliity `xx` VOLUME in ML …(Eqn.1)
`1/10 xx1000 = 100`
Number of EQUIVALENTS = `("no of m.e")/(1000) `
`=100/1000 = 0.10 `


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