1.

Calculatethe maximum workwhen24 g of oxygenare expandedisothermallyand reversiblyfrom apressureof1.6 xx 10^(5)Pa to 100Kpaat 298 K.

Answer»


Solution :Given :mass ofoxygen= W=24 g
Initialpressure`= P_(1)= 1.6 xx 10^(5)pa`
Finalpressure`= P_(2)=100kP_(a) = 100 xx 10^(3)Pa= 1 xx 10^(5) Pa`
Temperature=T =298 K
MOLARMASS ofoxygen`(O_(2)) = M_(O_(2)) = 32g mol^(-1)`
`W_(max)= ?`
Numberof molesof `O_(2)= n_(O_(2)) = (W)/(M_(O_(2)))= (24)/(32) = 0.75mol`
`W_(max) =- 2.303nRT log_(10) .(P_(1))/(P_(2))`
`=- 2.303xx 0.75 xx 8.314xx 298log_(10).(1.6 xx 10^(5))/(1xx 10^(5))`
`=- 2.303xx 0.75xx 8. 314xx 298xx log_(10) 1.6`
`=- 2.303 xx 0.75xx 8.314xx 298xx 0. 2041`
`=- 873.5 J`


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