1.

calculateth resonance energy of N_(2)O Delta_(f)H^(-) of N_(2)O = 82 kJ mol ^(-1) bond energy of N=O = 607 kJmol ^(-1) bond energy of O=O = 498 kJ mol ^(-1) nond energy of N = N = 418 kJ mol^(-1) bond energy of N= N = 946 kJ mol ^(-1)

Answer»

`82 kJ mol ^(-1)`
`-88 kJ mol ^(-1)`
`- 82 kJ mol ^(-1)`
`+ 88 kJ mol ^(-1)`

Solution :`NequivN(g) + 1/2 O_(2)(g)to N=N=0`
calculated value of `Delta_(F)H^(Theta)=`
`Delta_(f)H^(-)=[BE(NequivN)+1/2BE(=O)]`
`[BE(N=N)+BE(N=O)]`
`[946+1/2(498)]- [418+607]=170 kJ mol^(-1)`
Respmace energy = observed `Delta_(f)H^(Theta)` - calculated `Delta_(f)H^(Theta)`
= 82 -170 =-88 kJ `mol^(-1)`


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