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Calculate work done during isothermal reversible process when `5 mol` ideal gas is expanded so that its volume is doubled at `400K`.A. `-11.5 kJ`B. `- 344 kJ`C. 0D. `-2.8 kJ` |
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Answer» Correct Answer - A `W_("isoreversible") = -2.303nRT "log" (V_(2))/(V_(1))` `= -2.303 xx 5 xx 8.314 xx 400 xx log2` `= -2.303 xx 5 xx 8.314 xx 400 xx 0.3J` `= -11488.28J` |
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