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Calculate wedge_(m)^(@) for CaCl_(2) and MgSO_(4) from the following data: lamda^(@) (S cm^(2)mol^(-1)):Ca^(2+)=119.0,Mg^(2+)=106.0,Cl^(-)=76.3,SO_(4)^(2-)=160.0. |
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Answer» Solution :By Kohlrausch law, `wedge_(m)^(@)(CaCl_(2))=lamda_(Ca^(2+))^(@)+2lamda_(Cl^(-))^(@)=119.0" S "cm^(2)MOL^(-1)+2xx76.3" S "cm^(2)mol^(-1)` `=(119.0+152.6)" S "cm^(2)mol^(-1)=271.6" S "cm^(2)mol^(-1)` `wedge_(m)^(@)(MgSO_(4))=lamda_(Mg^(2+))^(@)+lamda_(SO_(4)^(2-))^(@)=106.0" S "cm^(2)mol^(-1)+160.0" S "cm^(2)mol^(-1)=266" S "cm^(2)mol^(-1)`. |
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