1.

Calculate value of (X+Y+Z)/(10), here X is O-N-O bond angle in NO_(3)^(-) Y is O-N-O bond angle in NO_(2)^(+) and Z is F-Xe-F adjacent bond angle in XeF_(4).

Answer»


Solution :`X=120(sp^(2)` hybridization)
Y=180 (sp -hybridization)
`Z=90(sp^(3)d^(2)` hybridization)
`(120+180+90)/(10)=(390)/(10)=39`


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