1.

Calculate total number of electron present in Cr having n + l + m = 6

Answer»

3
1
5
6

Solution :`Cr_(24) = 1s^(2) 2P^(6) 3s^(2) underset(3 + 1 + 1 = 5)underset(darr)(3p^(6)) "" underset(("ONE 'd' orbital"))underset(3 + 2 + 1 = 6)underset(darr)(3D^(5)4s^(1))`
Number of electrons having `n + L + m = 6` from `3d^(5) = 1`
Total `=1`


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