Calculate tje volume of 1 mole of a gas at exactly 20° c at a pressur

1.	Calculate tje volume of 1 mole of a gas at exactly 20° c at a pressure of 101.325 kpa
Answer» Answer: The VOLUME of 1 mole of gas is 24.055 L. Explanation: GIVEN data: No. of moles of gas, n = 1 Absolute TEMPERATURE, T = 20° C = 20 + 273.15 K = 293.15 K Pressure, *P = 101.35 kPa = 101.35 10³ Pa = 101.35 * 10³ * 9.86910⁻⁶ = 1 atm ...... [ ∵ 1 Pa = 9.869 10⁻⁶ atm] To find: Volume, V Using the IDEAL Gas LAW, we get PV = nRT Where, R = ideal gas constant = 0.08206 L. atm. mol−1** V = n(RT/V) Or, V = 1 * [(0.08206 * 293.15) / 1] = 24.055 L

Calculate tje volume of 1 mole of a gas at exactly 20° c at a pressure of 101.325 kpa

Answer»

Answer:

The VOLUME of 1 mole of gas is 24.055 L.

Explanation:

GIVEN data:

No. of moles of gas, n = 1

Absolute TEMPERATURE, T = 20° C = 20 + 273.15 K = 293.15 K

Pressure, P = 101.35 kPa = 101.35 * 10³ Pa = 101.35 * 10³ * 9.869*10⁻⁶ = 1 atm ...... [ ∵ 1 Pa = 9.869 * 10⁻⁶ atm]

To find: Volume, V

Using the IDEAL Gas LAW, we get

PV = nRT

Where, R = ideal gas constant = 0.08206 L. atm. mol−1

V = n(RT/V)

Or, V = 1 * [(0.08206 * 293.15) / 1] = 24.055 L