1.

Calculate the work done during combustion of 0.138 kg of ethanol, C_(2)H_(5)OH(l) at 300 K. Given : R=8.314 JK^(-1)mol^(-1), molar mass of ethanol =46g mol^(-1)

Answer»

`-7482J`
`7482J`
`-2494J`
`2494J`

SOLUTION :The CONBUSTION of ethanol, involves the following reaction .
`C_(2)H_(5)(L)+3O_(2)(g)to2CO_(2)+3H_(2)O`
Given,
Mass of ethanol `=0.138kg=138g`
Temperature `=300K`
`R=8.314JK^(-1)mol^(-1)`
Molar mass of ethanol `=46gmol^(-1)`
No. of moles of ethanol `=("Mass of ethanol")/("Molar mass of ethanol")`
`=(138)/(46)=3`
WORK done (W) during combustion of 0.138 Kg of `C_(2)H_(5)OH=nRT`
`W=nRT`
`W=3xx8.31JK^(-1)mol^(-1)xx300K`
`W=7482.6J`
`~~7482J`


Discussion

No Comment Found

Related InterviewSolutions