1.

Calculate the work done by a force of 30 N in lifting load of 2g to a height of 10 m (g = 10 ms^(-2)).

Answer»

Solution :GIVEN : F=30 N, load(m)=2KG, height=10 m,`g=10ms^(-2)`
Gravitationalforce Fmg=30 N
The distance moved h=10 m
work done on the OBJECT `W=Fh=30xx10=300J`


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