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Calculate the weight of `MnO_(2)` required to react with `HCl` having specific gravity `1.2gm//ml`. `4%` by mas necked to produce `1.8L` of `Cl_(2)` at STP by reaction. |
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Answer» Correct Answer - 8 `MnO_(2)+4HClto MnCl_(2)+Cl_(2)+2H_(2)O` `100gm` sol contains `4gm HCl` `100/1.2 ml` sol contains `4 gm HCl` `nCl_(2)=1.8/22.4=0.0805` `W_(MnO_(2))=0.0805xx87=8gm` |
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