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Calculate the wavelength of the radiation emitted when an electron in a hydrogen atom makes a transition from an energy level with n=4 to n=1 |
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Answer» Explanation:According to BALMER formulaWave no = RH [1/n1^2 – 1/N2^2]Here n1 = 1 , n2 = 4, RH = 109678Putting these values in the equation we getWave number =109678(1/1^2 - 1/4^2) = 109678 x 15/16Also λ = 1/ wave numberTherefore λ = 16 / 109678 x 15 = 102823.125 nm |
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