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Calculate the wavelength of a photon that traveled from 5^th orbit to 2^nd orbit.(a) 434 nm(b) 456 nm(c) 863 nm(d) 268 nmThe question was asked in semester exam.My question comes from Bohr’s Model for Hydrogen Atom topic in division Structure of Atom of Chemistry – Class 11

Answer» CORRECT answer is (a) 434 nm

The explanation is: The ENERGY of an nth orbit in a hydrogen atom is given by the formula En = -RH/n^2, where is the energy of nth orbit and RH is the Rydberg CONSTANT. E5 – E2 = -4.58 x 10^-19J. λ(wavelength) = c(SPEED of light)h(Planck’s constant)/E = 434nm.


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